Hello guys, here is todays post. Its related to recurring decimals ending with 9 like 1/9 1/19 1/29 etc...
So the method goes as follows:
Steps:
1. The last digit will always be 1. eg 1/19= .1
2. The ratio of multiplication will be tens-1 ie 2 for 19, 3 for 29, 5 for 49 and so on.. Here for 1/19 -Ratio= 1:2
3. Start multiplying from the end and dont forget carry overs..
Continue till u get (number-1). So, here we must continue till we get 19-1=18
So, we have .9 4 7 3 6 8 4 2 1
Here after 8, we have 8*2=16. So 6 then 6*2+1=13 So 3. 3*2+1=7. 7*2=14 So 4. 4*2+1=9. 9*2=18!!! So stop here
4.Now complement the digits with 9 to the left.. means 1=8 2=7 3=6 and 4=5. So we get final answer as
0.052631578/947368421. So fast!!
Source: Ekadikha Purva
Examples:
1/29=0.03448275862068/
1/49=0.020408163265306122448/
Try 1/69 1/79.. I am sure you will write within 3 minutes.
Lets see who gets this logic.. Its gonna be tough, very tough!!!
So the method goes as follows:
Steps:
1. The last digit will always be 1. eg 1/19= .1
2. The ratio of multiplication will be tens-1 ie 2 for 19, 3 for 29, 5 for 49 and so on.. Here for 1/19 -Ratio= 1:2
3. Start multiplying from the end and dont forget carry overs..
Continue till u get (number-1). So, here we must continue till we get 19-1=18
So, we have .9 4 7 3 6 8 4 2 1
Here after 8, we have 8*2=16. So 6 then 6*2+1=13 So 3. 3*2+1=7. 7*2=14 So 4. 4*2+1=9. 9*2=18!!! So stop here
4.Now complement the digits with 9 to the left.. means 1=8 2=7 3=6 and 4=5. So we get final answer as
0.052631578/947368421. So fast!!
Source: Ekadikha Purva
Examples:
1/29=0.03448275862068/
1/49=0.020408163265306122448/
Try 1/69 1/79.. I am sure you will write within 3 minutes.
Lets see who gets this logic.. Its gonna be tough, very tough!!!
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